You are viewing an old version of this page. View the current version.

Compare with Current View Page History

« Previous Version 7 Next »

The Integral Form of Newton's Second Law and Impulse     null

The Law of Change for the Momentum and External Force model can in principle be integrated:

Unknown macro: {latex}

\begin

Unknown macro: {large}

[ \int_{\vec

Unknown macro: {p}

_{i}}^{\vec

_{f}} d\vec

Unknown macro: {p}

= \int_{t_{i}}^{t_{f}} \sum_

Unknown macro: {rm ext}

\vec

Unknown macro: {F}

\:dt]\end

The left hand side of this expression is simple, and after some rearrangement, the equation becomes:

Unknown macro: {latex}

\begin

Unknown macro: {large}

[ \vec

Unknown macro: {p}

_

Unknown macro: {f}

= \vec

_

Unknown macro: {i}

+ \int_{t_{i}}^{t_{f}} \sum_

Unknown macro: {rm ext}

\vec

Unknown macro: {F}

\:dt]\end

In principle, it might be useful to leave the integral over force explicit in this equation, but in practice it is not useful. If a known force which is an easily integrable function of time is applied, then it is usually just as simple and more intuitive to use the traditional F = ma approach (followed by regular kinematics).

The utility of this equation actually lies in the reverse approach: using what is known about momentum to learn about the force. To facilitate this, we define the impulse associated with a force as:

Unknown macro: {latex}

\begin

Unknown macro: {large}

[ \vec

Unknown macro: {J}

= \int \vec

Unknown macro: {F}

\:dt ]\end

With this definition, the integral form of the Law of Change can be written:

Unknown macro: {latex}

\begin

Unknown macro: {large}

[ \vec

Unknown macro: {p}

_

Unknown macro: {f}

= \vec

_

Unknown macro: {i}

+ \sum_

Unknown macro: {rm ext}

\vec

Unknown macro: {J}

]\end

null Off the Wall (Simple problem illustrating the definition of impulse and the utility of an initial-state final-state diagram.)

  • No labels