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Overview

Distinguishable and indistinguishable particles have been considered. Consider the

...

single-particle

...

partition

...

function

...

among

...

distinguishable

...

particles.

...

Label

...

and

...

assign

...

criteria

...

among

...

different

...

particles.

...

Apply

...

the

...

Boltzman

...

approximation

...

at

...

high

...

temperature,

...

low

...

density,

...

and

...

high

...

mass

...

to

...

indistinguishable

...

particles

...

and

...

obtain

...

the

...

relation

...

below.

...

Adjust

...

for

...

overcounting.

...

The

...

number

...

of

...

particles

...

is

...

much

...

less

...

than

...

the

...

number

...

of

...

state.

...

Apply

...

to

...

a

...

monoatomic

...

gas.

...

At

...

low

...

temperature

...

and

...

high

...

density,

...

the

...

Boltzman

...

approximation

...

is

...

not

...

good.

...

Different

...

types

...

of

...

statistics

...

have

...

been

...

mentioned.

{
Latex
} \[ Q = \frac{q_{\mbox{single}}^N}{N\!} \] {latex}

Today

...

a

...

diatomic

...

gas

...

is

...

considered.

...

In

...

a

...

solid,

...

atoms

...

are

...

fixed

...

in

...

space.

...

A

...

solid

...

solution

...

and

...

vibrations

...

in

...

a

...

solid

...

are

...

considered.

...

Degrees

...

of

...

freedom

...

in

...

a

...

diatomic

...

molecule

...

There

...

are

...

different

...

degrees

...

of

...

freedom

...

in

...

a

...

diatomic

...

molecule.

...

Below

...

is

...

a schematic.

Image Added

There are various contributions to the Hamiltonian of a single particle. Contributions include translation, rotation, vibration, electric, and nuclear. The diatomic molecule is part of an ideal gas. Separate the Hamiltonians. Separate the interactions and particles. Under the rigid rotor approximation, rotations do not see the changing bond length. The contributions of the Hamiltonian due to rotation and vibration are independent. When vibrations are large, though, the bond length is changing. The first excited electric state would be considered. McQuarrie considers the first excited nuclear state. Thermodynamics cares about derivatives of the partition function.

Latex
 \[  schematic.







!Diatomic_molecule_--_translation%2C_vibration%2C_rotation.PNG!






There are various contributions to the Hamiltonian of a single particle. Contributions include translation, rotation, vibration, electric, and nuclear. The diatomic molecule is part of an ideal gas. Separate the Hamiltonians. Separate the interactions and particles. Under the rigid rotor approximation, rotations do not see the changing bond length. The contributions of the Hamiltonian due to rotation and vibration are independent. When vibrations are large, though, the bond length is changing. The first excited electric state would be considered. McQuarrie considers the first excited nuclear state. Thermodynamics cares about derivatives of the partition function.






\hat H_{\mbox{single}} = \hat H_{\mbox{trans}} + \hat H_{\mbox{rot}} + \hat H_{\mbox{vib}} + \hat H_{\mbox{elec}} + \hat H_{\mbox{nucl}} \] 

The partition function is a measure of the number of thermally excited states. Consider the single-particle partition function.

Latex
 \[ 






The partition function is a measure of the number of thermally excited states. Consider the single-particle partition function.






q_{\mbox{single}} = q_{\mbox{trans}} \cdot q_{\mbox{rot}} \cdot q_{\mbox{vib}} \] 

There is a high temperature approximation. Assuming "normal conditions" the Boltzman approximation can be used.

Latex
 \[ 






There is a high temperature approximation. Assuming "normal conditions" the Boltzman approximation can be used.






Q_{\mbox{sys}} = \frac{q_{\mbox{single}}^N}{N\!}
</math>
<br>

</center>

h2. Translation

Look at the center of mass when considering the translational component of the single-particle partition function.

<center>

<br>

<math>q \] 

Translation

Look at the center of mass when considering the translational component of the single-particle partition function.

Latex
 \[ q_{\mbox{trans}} = \left ( \frac
{2 \pi ( m_1 + m_2 ) k_B T}
{n^2} \right )^{\frac{3}{2}} \] 

Vibrations

There is interest in expressions of

Latex
 \[ q






h2. Vibrations

There is interest in expressions ofq_{\mbox{rot}} \] 

and

Latex
 \[ qandq_{\mbox{vib}} \] 

and

...

energy

...

spectrum.

...

Diatomic

...

molecules

...

see

...

a

...

potential

...

well

...

and

...

there

...

is

...

an

...

equilibrium

...

bond

...

length.

...

The deviation is

Latex
 \[ \zeta \] 

, and the term

Latex
 \[  deviation is\zeta, and the term\mbox{De} \] 

is

...

the

...

energy

...

required

...

to

...

dissociate.

...

Assuming

...

the

...

vibrations

...

are

...

small,

...

the

...

energy

...

associated

...

with

...

vibrating

...

bonds

...

can

...

be

...

expressed

...

with

...

a

...

Taylor

...

expansion.

...


!Potential_versus_spacing_--_Ro.PNG!

Latex
 \[ 




U( \zeta ) = U(0) + \left ( \frac{\partial U}{\partial \zeta} \right )_{\zeta = 0} \zeta + \frac {1}{2} \left ( \frac{\partial^2 U}{\partial \zeta^2} \right )_{\zeta = 0 } \zetazeta^2 ^2 + ... \] 

The first term,

Latex
 \[ 






The first term,U(0) \] 

,

...

is

...

constant,

...

and

...

the

...

second

...

term

...

is

...

equal

...

to

...

zero

...

since

...

there

...

is

...

no

...

force.

...

The

...

second-order

...

term

...

is

...

proportional

...

to

...

the

...

strength

...

of

...

the

...

bond

...

between

...

two

...

particles.

...

There

...

is

...

a

...

force

...

constant

...

between

...

two

...

particles.

...

Write

...

the

...

Hamiltonian

...

with

...

the

...

approximation

...

of

...

small

...

vibrations.

Latex
 \[ 






\hat H_{\mbox{vibr}} = \frac{\hbar^2}{2 m_r} \frac{\partial^2}{\partial \zeta^2} + \frac{1}
{2} f \zeta^2




 \] 
Latex
 \[ m_r = \frac{m_1 m_2}{m_1 + m_2}



The first term is a kinetic contribution, and the force  \] 

The first term is a kinetic contribution, and the force constant,f,

...

is

...

a

...

property

...

of

...

the

...

molecule.

...

Consider

...

the

...

quantum

...

mechanical

...

solutions

...

of

...

a

...

harmonic

...

oscillator.

Latex
 \[ 






\epsilon_n = \left ( n + \frac{1}{2} 
\right ) h \nu




 \]

Wiki Markup
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<P> </P>{html}

Latex
 \[ n=0,1,2

...

 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ \nu = \frac{1}{2 \pi} \sqrt{\frac{f}{m}} \] 

There is a relation between a spring constant and mass. Light masses or masses with a stiff spring vibrate rapidly. Write the mini-partition function. and simplify with the relation pertaining to a geometric series.

Latex
 \[ 






There is a relation between a spring constant and mass. Light masses or masses with a stiff spring vibrate rapidly. Write the mini-partition function. and simplify with the relation pertaining to a geometric series.






q_{\mbox{vib}} = \sum_n^{\infty} e^{-\beta \epsilon_n}




} \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ q_{\mbox{vib}} = \sum_{n=0}^{\infty} e^{\left ( n + \frac{1}{2} \right ) h \nu}

...

 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ q_{\mbox{vib}} = e^{\beta \frac{h \nu}{2}} \sum_{n=0}^{\infty} e^{\beta h \nu n

...

} \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ \mbox{Geometric Series}

...

 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ x < 1 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ \sum_{n = 0}^{\infty} x^n = \frac{1}{1-x}

...

 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ q_{\mbox{vib}} = \frac{e^{-\beta \frac{h \nu}{2}}}{1-e^{-\beta h \nu}} \] 

Express in terms of the characteristic vibrational temperature,

Latex
 \[ 






Express in terms of the characteristic vibrational temperature,\theta_{\nu}.






\theta_{\nu} \] 

.

Latex
 \[ \theta_{nu} = \= \frac{h \nu}{k_B}




 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ q_{\mbox{vib}} = \frac{e^{-\frac{\theta_{\nu}}{2 T}}}{1-e^{-\frac{\theta_{\nu}}{2 T}}} \] 

The characteristic termperature,

Latex
 \[ 






The characteristic termperature,\theta_{\nu} \] 

,

...

is

...

typically between

Latex
 \[ 3000 between3000 - 6000 K \] 

.

...

Calculate

...

the

...

probability

...

of

...

being

...

in

...

a

...

certain

...

state.

Latex
 \[ 






P_n = \pi_n




 \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ P_n = \frac{e^{-\beta \epsilon_n}}{q_{\mbox{vib}}}

...

 \pi_{n>0} \] 

A general expression of being in any state other than the ground state is below, as well as a calculation at

Latex
 \[ 300 K \] 

and a characteristic temperature of

Latex
 \[ 3000 K \] 

.

Latex
 \[ 






A general expression of being in any state other than the ground state is below, as well as a calculation at300 Kand a characteristic temperature of3000 K.






\pi_{n>0} = 1 - \pi_0




\pi_{n>0}  \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ \pi_{n>0} = e^{-10

...

} \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ \pi_{n>0} \approx 10^{-5}

...

 \] 

The probability of a molecule being in an excited state is very small. It is hard to excite a vibrational state above the ground state.

Rotation

Rotational motion is associated with angular momentum. The rotation of a diatomic molecule can be considered equivalent to the rotation of one particles moving freely along a sphere with fixed radius,

Latex
 \[ R_0 \] 

, and a reduced mass. Consider the Hamiltonian. The term

Latex
 \[ I \] 

is the moment of inertia and an expression of the eigenvalues,

Latex
 \[ \epsilon_j \] 

, to the spherical coordinate problem is below.

!Diatomic_molecule_--_rotation_with_axis.PNG!

Latex
 \[ 




\hat H = -\frac{\hbar^2}{2I} \left ( \frac{1}{\sin \theta} \frac{\partial}{\partial \theta} \left ( \sin \theta \frac{\partial}{\partial \theta} \right ) + \frac{1}{\sin^2 \theta} \frac{\partial^2}{\partial r^2} \right ) \] 
Latex
 \[ 




I = m_R R_0^2




 \] 
Latex
 \[ \epsilon\epsilon_j = \frac{\partial ( \zeta + 1 ) h^2}{8 \pi^2 I} \] 
Latex
 \[ 




j = 0, 1, 2






Identify the Hamiltonian, \] 

Identify the Hamiltonian, solve with Schrodinger or remember the energy spectrum. In an unsymmetric molecules, the two masses are not equivalent. A summation in the mini-partition function is not as easy as the vibrational case. Consider two limits.

Latex
 \[  solve with Schrodinger or remember the energy spectrum. In an unsymmetric molecules, the two masses are not equivalent. A summation in the mini-partition function is not as easy as the vibrational case. Consider two limits.






q_{\mbox{rot}} = \sum_{\epsilon_j} = w_j e^{\beta \epsilon_j}




 \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ q_{\mbox{rot}} = \sum_{\epsilon_j} = (2j + 1) e^{-j (j+1) \frac{\theta}{T

...

} } \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ \theta_r = \frac{h^2}{8 \pi^2 I k_N}

...

 \] 

Case 1

The first case involves high temperatures, or temperatures much greater than\theta_r.

...

If

...

the

...

temperature

...

is

...

large,

...

the

...

exponential

...

term

...

goes

...

to

...

zero.

...

States

...

are

...

dense,

...

and

...

it

...

is

...

possible

...

to

...

approximate

...

with

...

an

...

integral.

Latex
 \[ 






q_{\mbox{rot}} = \int (2j + 1) e^{-j (j+1) \frac{\theta}{T}} dj




q_{\mbox{rot}}  \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ q_{\mbox{rot}} = \frac{T}{\theta_r}

...

 \] 

Case 2

Consider when the temperature is close to\theta_r.

...

Caclulate

...

a

...

few

...

of

...

the

...

terms,

...

and

...

see

...

that

...

the

...

terms

...

decrease

...

rapidly.

...

Assume

...

that

...

the

...

larger

...

terms

...

are

...

zero.

...

Consider

...

the

...

first

...

couple

...

terms

...

of

...

the

...

summation.

Latex
 \[ 






q_{\mbox{rot}} = 1 + 3 e ^e^{-\frac{2 \theta_r}{T}} + 5 e ^e^{-\frac{6 \theta_r}{T}} + ...






There is overcounting of the number of states with symmetric molecules. Rotational degrees of freedom are coupled. Read MacQuarrie  \] 

There is overcounting of the number of states with symmetric molecules. Rotational degrees of freedom are coupled. Read MacQuarrie 6-4.

...

The

...

level

...

of

...

quantum

...

mechanics

...

is

...

above

...

what

...

is

...

required.

...

There

...

is

...

inversion

...

of

...

the

...

nucleus,

...

two

...

indistinguishable

...

configurations,

...

and

...

overcounting.

...

Regarding

...

the

...

quiz,

...

one

...

should

...

be

...

able

...

to

...

do

...

a

...

problem

...

with

...

a

...

symmetric

...

molecule.

...

Correction

...

for

...

overcounting

...

The

...

mini-partition

...

function

...

is

...

a

...

measure

...

of

...

the

...

number

...

of

...

thermally

...

accessible

...

states.

...

The

...

mini-partition

...

function

...

of

...

rotation

...

is

...

written

...

below

...

in

...

the

...

first

...

case

...

wherein

...

the

...

temperature

...

is

...

much

...

greater

...

than\theta_r.

Latex
 \[ 






q_{\mbox{rot}} = \frac{T}{2 \theta_r}






The case where the temperature is less  \] 

The case where the temperature is less than\theta_rrequires

...

rigorous

...

quantum

...

mechanical

...

treatment

...

(really

...

onlyH_2!).

...

Calculate

...

the

...

probability

...

to

...

be

...

in

...

a

...

certain

...

state.

Latex
 \[ 






P_j = \frac{N_j}{N} \] 
Latex
 \[ 




P_j = \frac{(2j + 1) e^{-j (j+1) \frac{\theta_r}{T}}}{q_{\mbox{rot}}}






Other states are seen other than the lowest one. A graph is below.



 \] 

Other states are seen other than the lowest one. A graph is below.

!Nj_n_versus_j.PNG!

...

Deriving Thermodynamic Quantities from Partition Function

From the single-partition

...

function,

...

build

...

the

...

entire

...

system.

Latex
 \[ 






Q_{\mbox{sys}} = \frac{\left ( q_{\mbox{trans}} \cdot q_{\mbox{rot}} \cdot q_{\mbox{vib}} \right )^N}{N!}




\!} \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ F = -k_B T \ln Q

...

 \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ F = -k_B T \left ( \ln q_{\mbox{trans}} + \ln q_{\mbox{rot}} + \ln q_{\mbox{vib}} - \ln N\! \right )

...

 \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ F = F_{\mbox{trans}} + F_{\mbox{rot}} + F_{\mbox{vibr}} \] 

Pressure

Calculate the pressure. Only the translational component of the partition function is proportional to volume.

Latex
 \[ 



h2. Pressure

Calculate the pressure. Only the translational component of the partition function is proportional to volume.






P = - \left ( \frac{\partial F}{\partial V} \right )_{N, T}




 \ln q_{\mbox{trans}} = \left ( \frac{2 \pi \left (m_1 + m_2 \right ) k_B T} {n^2}
 \right )^{\frac
{3}{2} V} \] 
Latex
 \[ 




P = \frac{N k_B T}{V}






This expression is the same as for a monoatomic gas. The ideal gas equation holds for both monoatomic and diatomic gases.

h2. Heat Capacity

Calculate the heat capacity. Decouple energies and heat capacities.






 \] 

This expression is the same as for a monoatomic gas. The ideal gas equation holds for both monoatomic and diatomic gases.

Heat Capacity

Calculate the heat capacity. Decouple energies and heat capacities.

Latex
 \[ E = k_B T^2 \left (\frac{\partial \ln Q}{\partial T} \right )_{N, V} \] 
Latex
 \[ 




E = E_{\mbox{trans}} + E_{\mbox{rot}} + E_{\mbox{vibr}}




 \] 
Latex
 \[ C_v = C_{v, \mbox{trans}} + C_{v, \mbox{rot}} + C_{v, \mbox{vibr}}



h3. Translational energy

Below is an expression of the translational energy



 \] 

Translational energy

Below is an expression of the translational energy

Latex
 \[ 


E_{\mbox{trans}} = \frac{3}
{2} N k_B T






h3. Rotational energy

An expression of the rotational energy is below. Consider at normal temperature and a system that is  \] 

Rotational energy

An expression of the rotational energy is below. Consider at normal temperature and a system that is notH_2.

...

An

...

expression

...

of

...

the

...

rotational

...

partition

...

function

...

is

...

also

...

below.

Latex
 \[ 






E_{\mbox{rot}} = N k_B T^2 \left ( \frac{ \partial \ln q_{\mbox {rot}}}{\partial T} \right )_{N, V}




 \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ E_{\mbox{rot}} = N k_B T \] 

Vibrational energy

The vibrational energy is expressed below.

Latex
 \[ 






h3. Vibrational energy

The vibrational energy is expressed below.






E_{\mbox{vibr}} = N k_B T^2 \left ( \frac{ \partial \ln q_{\mbox{vibr}}}{\partial T} \right )_{N, V}




} \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ E_{\mbox{rot}} = N k_B T \left ( \frac{ \frac{h \nu}{k_B T}}{e^{\frac{h \nu}{k_B T}} - 1} \right ) + \frac{N h \nu}{2} \] 

Analyze the vibrational energy with two limits.

Case 1

In the first case, consider the vibrational energy as the temperature approaches infinity. The expression of vibrational energy can be written in terms ofx, and is written below. As the temperature approaches infinity,xapproaches zero.

Latex
 \[ x = \frac
</math>
<br>

</center>

Analyze the vibrational energy with two limits.

h4. Case 1

In the first case, consider the vibrational energy as the temperature approaches infinity. The expression of vibrational energy can be written in terms of <math>x</math>, and is written below. As the temperature approaches infinity, <math>x</math> approaches zero.

<center>

<br>

<math>x = \frac
{h \nu}
{k_B T}
</math>
<br>

<math>\lim\_
 \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ \lim_{x \to 0}

...

 \frac

...

 {x}

...

{e^x - 1}

...

 = 1 \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ E_{\mbox{vibr}} = N k_B T + \frac {N h \nu}{2} \] 

Case 2

An expression of the vibrational energy in the case of temperature much less than

Latex
 \[ \theta_v \] 

.

Latex
 \[ 1</math>
<br>

<math>E_{\mbox
{vibr}

= N k_B T + \frac
{N h \nu}{2}






h4. Case 2

An expression of the vibrational energy in the case of temperature much less than\theta_v.






E_{\mbox{vib}} = \frac{N h \nu}
}
{2} \] 

Translational component of heat capacity

The translational component of heat capacity is found by differentiating the translational energy with respect to temperature.

Latex
 \[ C(






h3. Translational component of heat capacity

The translational component of heat capacity is found by differentiating the translational energy with respect to temperature.






C{v, \mbox{trans}}) = \frac{\partial E_{\mbox{trans}} }{\partial T}




C{ \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ C(v, \mbox{trans}

...

) = \frac{3 N k_B}{2} \] 

Rotational component of heat capacity

The relation below of the rotational component of heat capacity is used unless the temperature is very low or for

Latex
 \[ H_2 \] 

.

Latex
 \[ C(
</math>
<br>

</center>

h3. Rotational component of heat capacity

The relation below of the rotational component of heat capacity is used unless the temperature is very low or for <math>H_2</math>.

<center>

<br>

<math>C{v, \mbox{rot}}) = \frac{\partial E_{\mbox{rot}} }
{\partial T}




C{} \] 

Wiki Markup
{html}<p>{html}

Latex
 \[ C(v, \mbox{rot}

...

) = N k_B \] 

Vibrational component of heat capacity

The expression of the vibrational component of heat is below and is evaluated in two cases.

Latex
 \[ C(






h3. Vibrational component of heat capacity

The expression of the vibrational component of heat is below and is evaluated in two cases.






C{v, \mbox{vibr}}) = \frac{\partial E_{\mbox{vib}} }{\partial T}

}</math>
<br>

</center>

h4. Case 1

The temperature can be evaluated in the case of temperature much lower than <math>\theta_r</math>.
 \] 

Case 1

The temperature can be evaluated in the case of temperature much lower than

Latex
 \[ \theta_r \] 

.

Latex
 \[ C(
<center>

<br>

<math>C{v, \mbox{vibr}}) = 0</math>

<br>

</center>

h4. Case 2

An express of the vibrational component of heat capacity in the case of temperature greater than <math>\theta_ 0 \] 

Case 2

An express of the vibrational component of heat capacity in the case of temperature greater than

Latex
 \[ \theta_r \] 

is below.

Latex
 \[Cr</math> is below.

<center>

<br>

<math>C{v, \mbox{vibr}} = N k_B<B \] 

Total heat capacity

The total heat capacity is considered in two cases.

Case 1

Consider when the temperature is much less than

Latex
 \[ \theta_{\nu} \] 

and greater than

Latex
 \[ \theta_r \] 

.

Latex
 \[ C(/math>

<br>

</center>

h3. Total heat capacity

The total heat capacity is considered in two cases.

h4. Case 1

Consider when the temperature is much less than <math>\theta\_
{\nu}

</math> and greater than <math>\theta_r</math>.
<center>

<br>

<math>C{v, \mbox{tot}}) = \frac
 {3}{2} N k_B + N k_B + 0




C{v, \mbox{tot}}  \] 

Wiki Markup
{html}
<P> </P>{html}

Latex
 \[ C(v, \mbox{tot}) = \frac{5}{2} N k_B \] 

Case 2

An expression of the heat capacity is below in the case of the temperature greater than or equal to

Latex
 \[ \theta_v \] 

and much greater than

Latex
 \[ \theta_r \] 
Latex
 \[ C(



h4. Case 2

An expression of the heat capacity is below in the case of the temperature greater than or equal to\theta_vand much greater than\theta_r






C{v, \mbox{tot}}) = \frac{3}
{2} N k_B + N k_B + N k_B




C{ \] 

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 \[ C(v, \mbox{tot}

...

) = \frac{7}{2}

...

 N k_B 

...

\] 

Comments

Define different kinds of motion. Solve the Schrodinger equation. Evaluate as well as possible. Take limits in the rotational case. Boltzman is a system approximation. Don't need to be too occupied with the math.

Configurational Properties

A figure below is of a mixture of atoms in a solid. Consider some arrangement on a lattice of atoms and vacancies or a binary mix. In general different arrangements are associated with different energies. Consider

Latex
 \[ M \] 

sites with

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 \[ N \] 

atoms of one kind. The term

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 \[ x \] 

is the concentration.

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 \[ M \mbox{sites} \] 

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 \[ N \mbox{atoms} \] 

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 \[ x = \frac{N}{M} \] 

Assume now that the energy is only a function of concentration. Fix the concentration. With

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 \[ N \] 


fixed, there is only one energy. Treat in terms of a canonical or microcanonical ensemble. The number of ways to distribut

Latex
 \[ eN \] 

distinguishable particles on

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 \[ M \] 

sites is expressed below in terms of

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 \[ \Omega (E) \] 

.

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 \[ Q = \Omega (E) \cdot e^{-\beta E} \] 

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 \[ \Omega (E) = \frac{M!}{N!(M-N)!

...

} \] 

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 \[ F = E - TS \] 

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 \[ F = E - k_B T \ln \Omega

...

 \] 

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 \[ S = k_B \ln \Omega \] 

The term

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 \[ S \] 

is the configurational entropy. Construct a phase diagram. Consider an electronic or vibrational shift. Configurational entropy is most important. Below is an expression simplified with Stirling's approximation. The configurational entropy can be expressed as a function of concentration.

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 \[ 






The termSis the configurational entropy. Construct a phase diagram. Consider an electronic or vibrational shift. Configurational entropy is most important. Below is an expression simplified with Stirling's approximation. The configurational entropy can be expressed as a function of concentration.






S_{\mbox{config}} = k_B \ln \left ( \frac{M!}{N! (M-N)!} \right )




 \] 

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 \[ S_{\mbox{config}} = k_B ((M - N) \ln M + N \ln M - N \ln N - (M - N) \ln (M - N)

...

 \] 

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 \[ S_{\mbox{config}} = -k_B \left ( \frac{N}

...

 {M} \ln \frac{N}{M}

...

 + \frac

...

{(N-M)}

...

 {M} \ln \frac {M-N}{M}

...

 \right ) \] 

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 \[ S_{\mbox{config}} = 

...

-k_B M ( x \ln x + (1 - x) \ln (1 - x)) \] 

The expression above is of the ideal solid solution configurational entropy.

Calculate the propert of the system with increased

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 \[ T \] 

. Consider phase diagrams. An expression of Hemholtz free energy is below.

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 \[ F</math>

<br>

</center>

The expression above is of the ideal solid solution configurational entropy.

<p>
</p>

Calculate the propert of the system with increased <math>T</math>. Consider phase diagrams. An expression of Hemholtz free energy is below.

<center>

<br>

<math>F = E - TS</math>

<br>

<math>F TS \] 

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 \[ F = E

...

_

...

{G, ST = 0}

...

 - T (S_{\mbox{conf}} + S_{\mbox{el}} + S_{\mbox{vibr}} )

...

 \] 

The largest impact is from the configurational entropy.