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h4. Using Algebra
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The magnitude of the momentum before and after the collsion is the same (mbvb), which can easily lead to the conclusion that there has been no change. Thinking about the situation, however, should quickly convince you that the ball has certainly been acted on by some force, which implies that a change did occur. Carefully drawing the initial-state final-state diagram below (taking special note of the coordinate system) shows the resolution to this difficulty. |
Image Added | Image Added | Initial State | Final State |
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Mathematical Representation The ball's initial x momentum is positive in our coordinates (+mbvb), while its final x momentum is negative (-- mbvb), giving a change of:
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=diag1} {color:red} *Diagrammatic Representation* {color}
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{warning}The [{_}magnitude{_}|magnitude] of the [momentum|momentum] before and after the collsion is the same ({*}{_}m{~}b{~}v{~}b{~}{_}{*}), which can easily lead to the conclusion that there has been no change. Thinking about the situation, however, should quickly convince you that the ball has certainly been acted on by some force, which implies that a change _did_ occur. Carefully drawing the [initial-state final-state diagram] below (taking special note of the coordinate system) shows the resolution to this difficulty.{warning}
|!ballreversei.png!|!ballreversef.png!|
||Initial State||Final State||
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{toggle-cloak:id=math1} {color:red} *Mathematical Representation* {color}
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The ball's initial {*}_x_{*} momentum is positive in our coordinates ({*}+{_}m{~}b{~}v{~}b{~}{_}{*}), while its final {*}_x_{*} momentum is _negative_ ({*}-- {_}m{~}b{~}v{~}b{~}{_}{*}), giving a change of:
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{latex}\begin{large}\[ J_{x} = -m_{b}v_{b} - m_{b}v_{b} = -2m_{b}v_{b}\]\end{large}{latex}
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where the negative sign indicates that the impulse is applied in the negative {*}_x_{*} direction, and so the impulse points leftward in this case.
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{card:Using Algebra}
{card:label=Adding Vectors to get Final Momentum}
h4. Adding to get the Final Momentum
We have defined impulse as the final [momentum|momentum] minus the initial [momentum|momentum], but subtracting [vectors|vector] can be confusing. Therefore, we will first consider a rearrangement of the definition of impulse. We can write:
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where the negative sign indicates that the impulse is applied in the negative x direction, and so the impulse points leftward in this case.
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| Using Algebra |
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| Using Algebra |
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label | Adding Vectors to get Final Momentum |
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Adding to get the Final MomentumWe have defined impulse as the final momentum minus the initial momentum, but subtracting vectors can be confusing. Therefore, we will first consider a rearrangement of the definition of impulse. We can write:
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\begin{large}\[ \vec{p}_{f} = \vec{p}_{i} + \vec{J} \] \end{large}{latex}
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Thus, we can consider the impulse as the [vector|vector ] we must _add _ to the initial [momentum|momentum ] to yield the final [momentum|momentum ].
We can use this formulation to draw a vector diagram representing the ball-wall collision. Remembering the rules for adding [vectors |vector] tail-to-tip, we can draw the following diagram which includes the impulse vector: Image Added Card |
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| Adding Vectors to get Final Momentum |
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| Adding Vectors to get Final Momentum |
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label | Subtracting Initial Momentum Vector from Final |
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Subtracting Initial Momentum from FinalIt is also possible to draw a vector representation of the regular definition of impulse
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!addimpulsevec.png!
{card:Adding Vectors to get Final Momentum}
{card:label=Subtracting Initial Momentum Vector from Final}
h4. Subtracting Initial Momentum from Final
It is also possible to draw a vector representation of the regular definition of impulse
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{latex}\begin{large}\[ \vec{J} = \vec{p}_{f} - \vec{p}_{i} \] \end{large}{latex}
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but drawing a vector equation that includes subtraction is tricky. We _must_ think of this equation in the following |
but drawing a vector equation that includes subtraction is tricky. We must think of this equation in the following way:
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way:
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{latex}\begin{large}\[ \vec{J} = \vec{p}_{f} + (- \vec{p}_{i}) \] \end{large}{latex}
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In other |
In other words, we must think of the right hand side as the final momentum _plus _ the _negative _ of the initial momentum vector. Since the negative of a vector is just the reversed vector, this leads to the picture:
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!addneginitvec.png!
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which gives the same impulse vector as the diagram above.
Image Added which gives the same impulse vector as the diagram above.
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