{composition-setup}{composition-setup}
{excerpt}The time rate of change of [velocity] of an object, or alternately the net [force] on the object divided by the object's [mass].{excerpt}
h2h4. Mathematical Representation
{latex}\begin{large}\[ \vec{a} = \frac{d\vec{v}}{dt} \qquad \mbox{or} \qquad \vec{a}=\frac{\sum \vec{F}}{m} \]\end{large}{latex}
h2h4. One-Dimensional Acceleration
h5. Utility of the One-Dimensional Case
As with all [vector] equations, the equations of kinematics are usually approached by separation into components. In this fashion, the equations become three simultaneous one-dimensional equations. Thus, the consideration of motion in one dimension with acceleration can be generalized to the three-dimensional case.
h5. Useful Digrammatic Representations
Several diagrammatic representations are commonly used to represent accelerated motion.
* [*Position vs. Time Graph*|position versus time graph]
* [*Velocity vs. Time Graph*|velocity versus time graph]
* [*Motion Diagram*|motion diagram]
h5. Deceleration
In physics, the term _acceleration_ denotes a vector, as does [velocity]. When the acceleration of an object points in the same direction as its [velocity], the object speeds up. When the acceleration of an object points in the direction opposite the object's [velocity], the object slows down. In everyday speech, we would call the first case "acceleration" and the second case "deceleration". In physics, both cases represent acceleration, but with a different relationship to the [velocity].
h5. Constant Acceleration
h6. Integration with Respect to Time
If acceleration is constant, the definition of acceleration can be integrated:
{latex}\begin{large}\[ \int_{v_{\rm i}}^{v} dv = \int_{t_{\rm i}}^{t} a\: dt \] \end{large}{latex}
For the special case of constant acceleration, the integral yields:
{latex}\begin{large} \[ v - v_{\rm i} = a(t-t_{\rm i}) \] \end{large}{latex}
which is equivalent to:
{latex}\begin{large} \[ v = v_{\rm i} + a (t-t_{\rm i}) \] \end{large}{latex}
We can now substitute into this equation the definition of velocity,
{latex}\begin{large}\[ v = \frac{dx}{dt}\]\end{large}{latex}
which gives:
{latex} \begin{large} \[ \frac{dx}{dt} = v_{\rm i} + a t - a t_{\rm i} \] \end{large}{latex}
We can now integrate again:
{latex} \begin{large} \[ \int_{x_{\rm i}}^{x} dx = \int_{t_{\rm i}}^{t} \left( v_{\rm i} - at_{\rm i} + a t\right)\:dt \] \end{large}{latex}
to find:
{latex} \begin{large} \[ x - x_{\rm i} = v_{\rm i} (t-t_{\rm i}) - a t_{\rm i} (t-t_{\rm i}) + \frac{1}{2}a( t^{2} - t_{\rm i}^{2}) \] \end{large}{latex}
We finish up with some algebra:
{latex}\begin{large}\[ x = x_{\rm i} + v_{\rm i} (t-t_{\rm i}) + \frac{1}{2} a (t^{2} - 2 t t_{\rm i} + t_{\rm i}^{2}) \] \end{large}{latex}
which is equivalent to:
{latex}\begin{large} \[ x = x_{\rm i} + v_{\rm i} (t-t_{\rm i}) + \frac{1}{2} a (t - t_{\rm i})^{2} \] \end{large}{latex}
h6. Integration with Respect to Position
The definition of acceleration can also be integrated with respect to position, if we use a calculus trick that relies on the chain rule. Returning to the definition of acceleration:
{latex}\begin{large}\[ \frac{dv}{dt} = a \] \end{large}{latex}
we would like to find an expression for _v_ as a function of _x_ instead of _t_. One way to achieve this is to use the chain rule to write:
{latex}\begin{large} \[ \frac{dv}{dx}\frac{dx}{dt} = a \] \end{large}{latex}
We can now elminate _t_ from this expression by using the defnition of velocity to recognize that _dx_/_dt_ = _v_. Thus:
{latex}\begin{large} \[ \frac{dv}{dx}v = a \] \end{large}{latex}
which is easily integrated for the case of constant acceleration:
{latex}\begin{large} \[ \int_{v_{\rm i}}^{v} v \:dv = \int_{x_{\rm i}}^{x} a \:dx \] \end{large}{latex}
to give:
{latex}\begin{large}\[ v^{2} = v_{\rm i}^{2} + 2 a (x-x_{\rm i}) \] \end{large}{latex}
h6. The Utility of Constant Acceleration
Stringing together a series of constant [velocity] segments is not usually a realistic description of motion, because real objects cannot change their velocity in a discontinuous manner. This drawback does _not_ apply to constant acceleration, however. Objects can have their acceleration changed almost instantaneously. Because of this, it is often reasonable to approximate a complicated motion by separating it into segments of constant acceleration.
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